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254085131 is a prime number
BaseRepresentation
bin11110010010100…
…00100000001011
3122201002212021102
433021100200023
51010021211011
641113532015
76203454656
oct1711204013
9581085242
10254085131
11120473a13
127111400b
1340842c41
1425a6089d
151748e73b
hexf25080b

254085131 has 2 divisors, whose sum is σ = 254085132. Its totient is φ = 254085130.

The previous prime is 254085113. The next prime is 254085203. The reversal of 254085131 is 131580452.

Together with previous prime (254085113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 254085131 - 26 = 254085067 is a prime.

It is a super-2 number, since 2×2540851312 = 129118507590574322, which contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 254085094 and 254085103.

It is not a weakly prime, because it can be changed into another prime (254085101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127042565 + 127042566.

It is an arithmetic number, because the mean of its divisors is an integer number (127042566).

Almost surely, 2254085131 is an apocalyptic number.

254085131 is a deficient number, since it is larger than the sum of its proper divisors (1).

254085131 is an equidigital number, since it uses as much as digits as its factorization.

254085131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 29.

The square root of 254085131 is about 15940.0480237671. The cubic root of 254085131 is about 633.3732980937.

The spelling of 254085131 in words is "two hundred fifty-four million, eighty-five thousand, one hundred thirty-one".