2541030254131 has 2 divisors, whose sum is σ = 2541030254132. Its totient is φ = 2541030254130.

The previous prime is 2541030254093. The next prime is 2541030254153. The reversal of 2541030254131 is 1314520301452.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2541030254131 - 2¹¹ = 2541030252083 is a prime.

It is a super-2 number, since 2×2541030254131² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2541030254093 and 2541030254102.

It is not a weakly prime, because it can be changed into another prime (2541030254731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1270515127065 + 1270515127066.

It is an arithmetic number, because the mean of its divisors is an integer number (1270515127066).

Almost surely, 2^{2541030254131} is an apocalyptic number.

2541030254131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2541030254131 is an equidigital number, since it uses as much as digits as its factorization.

2541030254131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 2541030254131 its reverse (1314520301452), we get a palindrome (3855550555583).

The spelling of 2541030254131 in words is "two trillion, five hundred forty-one billion, thirty million, two hundred fifty-four thousand, one hundred thirty-one".