Base | Representation |
---|---|
bin | 1001011101110110… |
… | …1011100000101011 |
3 | 20120002121021202201 |
4 | 2113131223200223 |
5 | 20201012440021 |
6 | 1100053241031 |
7 | 116654222314 |
oct | 22735534053 |
9 | 6502537681 |
10 | 2541140011 |
11 | 1094453113 |
12 | 5ab033177 |
13 | 316604b57 |
14 | 1a16bd60b |
15 | ed155591 |
hex | 9776b82b |
2541140011 has 2 divisors, whose sum is σ = 2541140012. Its totient is φ = 2541140010.
The previous prime is 2541139987. The next prime is 2541140033. The reversal of 2541140011 is 1100411452.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2541140011 - 221 = 2539042859 is a prime.
It is not a weakly prime, because it can be changed into another prime (2541140311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1270570005 + 1270570006.
It is an arithmetic number, because the mean of its divisors is an integer number (1270570006).
Almost surely, 22541140011 is an apocalyptic number.
2541140011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2541140011 is an equidigital number, since it uses as much as digits as its factorization.
2541140011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160, while the sum is 19.
The square root of 2541140011 is about 50409.7213937947. The cubic root of 2541140011 is about 1364.6130853805.
Adding to 2541140011 its reverse (1100411452), we get a palindrome (3641551463).
The spelling of 2541140011 in words is "two billion, five hundred forty-one million, one hundred forty thousand, eleven".
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