Base | Representation |
---|---|
bin | 1011100011100111011010… |
… | …11100111100101110111001 |
3 | 10022222110102101100100002122 |
4 | 11301303231130330232321 |
5 | 11312331321114441441 |
6 | 130014324211011025 |
7 | 5232013041352145 |
oct | 561635534745671 |
9 | 108873371310078 |
10 | 25413010312121 |
11 | 8108662894a63 |
12 | 2a25265899a75 |
13 | 112458a258973 |
14 | 63bdd3a58225 |
15 | 2e10b628d34b |
hex | 171ced73cbb9 |
25413010312121 has 2 divisors, whose sum is σ = 25413010312122. Its totient is φ = 25413010312120.
The previous prime is 25413010312103. The next prime is 25413010312141. The reversal of 25413010312121 is 12121301031452.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23834519607721 + 1578490704400 = 4882061^2 + 1256380^2 .
It is a cyclic number.
It is not a de Polignac number, because 25413010312121 - 222 = 25413006117817 is a prime.
It is not a weakly prime, because it can be changed into another prime (25413010312141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12706505156060 + 12706505156061.
It is an arithmetic number, because the mean of its divisors is an integer number (12706505156061).
Almost surely, 225413010312121 is an apocalyptic number.
It is an amenable number.
25413010312121 is a deficient number, since it is larger than the sum of its proper divisors (1).
25413010312121 is an equidigital number, since it uses as much as digits as its factorization.
25413010312121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 25413010312121 its reverse (12121301031452), we get a palindrome (37534311343573).
The spelling of 25413010312121 in words is "twenty-five trillion, four hundred thirteen billion, ten million, three hundred twelve thousand, one hundred twenty-one".
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