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254153120030401 is a prime number
BaseRepresentation
bin111001110010011010100010…
…011100000001111011000001
31020022212210121220211111121111
4321302122202130001323001
5231303021042211433101
62300312155334323321
7104350646145604624
oct7162324234017301
91208783556744544
10254153120030401
1173a87807554179
12246086b17b9541
13aba76c8578c67
1446a911044bdbb
151e5b18c63c251
hexe726a2701ec1

254153120030401 has 2 divisors, whose sum is σ = 254153120030402. Its totient is φ = 254153120030400.

The previous prime is 254153120030351. The next prime is 254153120030423. The reversal of 254153120030401 is 104030021351452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 251629978396801 + 2523141633600 = 15862849^2 + 1588440^2 .

It is a cyclic number.

It is not a de Polignac number, because 254153120030401 - 221 = 254153117933249 is a prime.

It is not a weakly prime, because it can be changed into another prime (254153120030441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127076560015200 + 127076560015201.

It is an arithmetic number, because the mean of its divisors is an integer number (127076560015201).

Almost surely, 2254153120030401 is an apocalyptic number.

It is an amenable number.

254153120030401 is a deficient number, since it is larger than the sum of its proper divisors (1).

254153120030401 is an equidigital number, since it uses as much as digits as its factorization.

254153120030401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 254153120030401 its reverse (104030021351452), we get a palindrome (358183141381853).

The spelling of 254153120030401 in words is "two hundred fifty-four trillion, one hundred fifty-three billion, one hundred twenty million, thirty thousand, four hundred one".