Base | Representation |
---|---|
bin | 1001011110001000… |
… | …0111100011001001 |
3 | 20120011210101200102 |
4 | 2113202013203021 |
5 | 20201312202213 |
6 | 1100134215145 |
7 | 120000136235 |
oct | 22742074311 |
9 | 6504711612 |
10 | 2542303433 |
11 | 109507821a |
12 | 5ab4b44b5 |
13 | 316921577 |
14 | 1a19035c5 |
15 | ed2d5158 |
hex | 978878c9 |
2542303433 has 2 divisors, whose sum is σ = 2542303434. Its totient is φ = 2542303432.
The previous prime is 2542303427. The next prime is 2542303453. The reversal of 2542303433 is 3343032452.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1495910329 + 1046393104 = 38677^2 + 32348^2 .
It is a cyclic number.
It is not a de Polignac number, because 2542303433 - 210 = 2542302409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2542303396 and 2542303405.
It is not a weakly prime, because it can be changed into another prime (2542303453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271151716 + 1271151717.
It is an arithmetic number, because the mean of its divisors is an integer number (1271151717).
Almost surely, 22542303433 is an apocalyptic number.
It is an amenable number.
2542303433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2542303433 is an equidigital number, since it uses as much as digits as its factorization.
2542303433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 29.
The square root of 2542303433 is about 50421.2597323788. The cubic root of 2542303433 is about 1364.8213093339.
Adding to 2542303433 its reverse (3343032452), we get a palindrome (5885335885).
The spelling of 2542303433 in words is "two billion, five hundred forty-two million, three hundred three thousand, four hundred thirty-three".
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