Base | Representation |
---|---|
bin | 1110110011001000100… |
… | …1011110001010100001 |
3 | 220022020201201102200222 |
4 | 3230302021132022201 |
5 | 13131143032222423 |
6 | 312444232052425 |
7 | 24240261601634 |
oct | 3546211361241 |
9 | 808221642628 |
10 | 254244414113 |
11 | 98908386408 |
12 | 41335b34115 |
13 | 1ac8a518631 |
14 | c43c3c9c1b |
15 | 693076d3c8 |
hex | 3b3225e2a1 |
254244414113 has 2 divisors, whose sum is σ = 254244414114. Its totient is φ = 254244414112.
The previous prime is 254244414043. The next prime is 254244414133. The reversal of 254244414113 is 311414442452.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 163359047329 + 90885366784 = 404177^2 + 301472^2 .
It is a cyclic number.
It is not a de Polignac number, because 254244414113 - 210 = 254244413089 is a prime.
It is not a weakly prime, because it can be changed into another prime (254244414133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127122207056 + 127122207057.
It is an arithmetic number, because the mean of its divisors is an integer number (127122207057).
Almost surely, 2254244414113 is an apocalyptic number.
It is an amenable number.
254244414113 is a deficient number, since it is larger than the sum of its proper divisors (1).
254244414113 is an equidigital number, since it uses as much as digits as its factorization.
254244414113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 61440, while the sum is 35.
Adding to 254244414113 its reverse (311414442452), we get a palindrome (565658856565).
The spelling of 254244414113 in words is "two hundred fifty-four billion, two hundred forty-four million, four hundred fourteen thousand, one hundred thirteen".
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