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254332049988011 is a prime number
BaseRepresentation
bin111001110101000001001011…
…011111101001100110101011
31020100111220110212010010122112
4321311001023133221212223
5231313434014244104021
62300530310352312535
7104366612202262622
oct7165011337514653
91210456425103575
10254332049988011
11740466868826a6
1224637308b4274b
13abbb5425cb418
1446b3a460a66b9
151e60b60e2ad5b
hexe7504b7e99ab

254332049988011 has 2 divisors, whose sum is σ = 254332049988012. Its totient is φ = 254332049988010.

The previous prime is 254332049987971. The next prime is 254332049988041. The reversal of 254332049988011 is 110889940233452.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 254332049988011 - 230 = 254330976246187 is a prime.

It is a super-2 number, since 2×2543320499880112 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (254332049988041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127166024994005 + 127166024994006.

It is an arithmetic number, because the mean of its divisors is an integer number (127166024994006).

Almost surely, 2254332049988011 is an apocalyptic number.

254332049988011 is a deficient number, since it is larger than the sum of its proper divisors (1).

254332049988011 is an equidigital number, since it uses as much as digits as its factorization.

254332049988011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14929920, while the sum is 59.

The spelling of 254332049988011 in words is "two hundred fifty-four trillion, three hundred thirty-two billion, forty-nine million, nine hundred eighty-eight thousand, eleven".