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254334314137 is a prime number
BaseRepresentation
bin1110110011011110000…
…0011010011010011001
3220022110222212211100111
43230313200122122121
513131334041023022
6312501203004321
724242433000061
oct3546740323231
9808428784314
10254334314137
11989540a9652
12413600696a1
131aca3033c07
14c44a30c3a1
1569385ca477
hex3b3781a699

254334314137 has 2 divisors, whose sum is σ = 254334314138. Its totient is φ = 254334314136.

The previous prime is 254334314093. The next prime is 254334314191. The reversal of 254334314137 is 731413433452.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 197619367936 + 56714946201 = 444544^2 + 238149^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-254334314137 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 254334314137.

It is not a weakly prime, because it can be changed into another prime (254334324137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127167157068 + 127167157069.

It is an arithmetic number, because the mean of its divisors is an integer number (127167157069).

Almost surely, 2254334314137 is an apocalyptic number.

It is an amenable number.

254334314137 is a deficient number, since it is larger than the sum of its proper divisors (1).

254334314137 is an equidigital number, since it uses as much as digits as its factorization.

254334314137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 362880, while the sum is 40.

Adding to 254334314137 its reverse (731413433452), we get a palindrome (985747747589).

The spelling of 254334314137 in words is "two hundred fifty-four billion, three hundred thirty-four million, three hundred fourteen thousand, one hundred thirty-seven".