Base | Representation |
---|---|
bin | 100101000000101110001… |
… | …010111001010111111001 |
3 | 100000010221120212112211112 |
4 | 211000232022321113321 |
5 | 313132333140410414 |
6 | 5224230351010105 |
7 | 351516463620326 |
oct | 45005612712771 |
9 | 10003846775745 |
10 | 2543395247609 |
11 | 8a0714347087 |
12 | 350b15b09935 |
13 | 155ac1cb5348 |
14 | 8b15b171b4d |
15 | 4625d711d3e |
hex | 2502e2b95f9 |
2543395247609 has 2 divisors, whose sum is σ = 2543395247610. Its totient is φ = 2543395247608.
The previous prime is 2543395247557. The next prime is 2543395247623. The reversal of 2543395247609 is 9067425933452.
2543395247609 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2543297731984 + 97515625 = 1594772^2 + 9875^2 .
It is a cyclic number.
It is not a de Polignac number, because 2543395247609 - 212 = 2543395243513 is a prime.
It is not a weakly prime, because it can be changed into another prime (2543395247639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271697623804 + 1271697623805.
It is an arithmetic number, because the mean of its divisors is an integer number (1271697623805).
Almost surely, 22543395247609 is an apocalyptic number.
It is an amenable number.
2543395247609 is a deficient number, since it is larger than the sum of its proper divisors (1).
2543395247609 is an equidigital number, since it uses as much as digits as its factorization.
2543395247609 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48988800, while the sum is 59.
The spelling of 2543395247609 in words is "two trillion, five hundred forty-three billion, three hundred ninety-five million, two hundred forty-seven thousand, six hundred nine".
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