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25434120000 = 263541811171
BaseRepresentation
bin10111101011111111…
…011101111101000000
32102122112210011111110
4113223333131331000
5404042113320000
615403445243320
71560165311232
oct275377357500
972575704443
1025434120000
11a871996893
124b19a03540
132524463163
141333cb0252
159dcd75850
hex5ebfddf40

25434120000 has 280 divisors, whose sum is σ = 84627935392. Its totient is φ = 6739200000.

The previous prime is 25434119927. The next prime is 25434120011. The reversal of 25434120000 is 2143452.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 21719415 + ... + 21720585.

Almost surely, 225434120000 is an apocalyptic number.

25434120000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 25434120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (42313967696).

25434120000 is an abundant number, since it is smaller than the sum of its proper divisors (59193815392).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

25434120000 is a wasteful number, since it uses less digits than its factorization.

25434120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1387 (or 1362 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 21.

Adding to 25434120000 its reverse (2143452), we get a palindrome (25436263452).

The spelling of 25434120000 in words is "twenty-five billion, four hundred thirty-four million, one hundred twenty thousand".