Base | Representation |
---|---|
bin | 111001110101001011011011… |
… | …011001000000111001001001 |
3 | 1020100112221212202022001100012 |
4 | 321311023123121000321021 |
5 | 231314124033322231324 |
6 | 2300535330324521305 |
7 | 104400451661562101 |
oct | 7165133331007111 |
9 | 1210487782261305 |
10 | 254343054102089 |
11 | 74050313370457 |
12 | 2463947a250235 |
13 | abbc5a7336524 |
14 | 46b43ab728201 |
15 | 1e610a702e20e |
hex | e752db640e49 |
254343054102089 has 2 divisors, whose sum is σ = 254343054102090. Its totient is φ = 254343054102088.
The previous prime is 254343054102017. The next prime is 254343054102157. The reversal of 254343054102089 is 980201450343452.
254343054102089 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 135166968533689 + 119176085568400 = 11626133^2 + 10916780^2 .
It is a cyclic number.
It is not a de Polignac number, because 254343054102089 - 28 = 254343054101833 is a prime.
It is not a weakly prime, because it can be changed into another prime (254343054102289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127171527051044 + 127171527051045.
It is an arithmetic number, because the mean of its divisors is an integer number (127171527051045).
Almost surely, 2254343054102089 is an apocalyptic number.
It is an amenable number.
254343054102089 is a deficient number, since it is larger than the sum of its proper divisors (1).
254343054102089 is an equidigital number, since it uses as much as digits as its factorization.
254343054102089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4147200, while the sum is 50.
The spelling of 254343054102089 in words is "two hundred fifty-four trillion, three hundred forty-three billion, fifty-four million, one hundred two thousand, eighty-nine".
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