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254343054102089 is a prime number
BaseRepresentation
bin111001110101001011011011…
…011001000000111001001001
31020100112221212202022001100012
4321311023123121000321021
5231314124033322231324
62300535330324521305
7104400451661562101
oct7165133331007111
91210487782261305
10254343054102089
1174050313370457
122463947a250235
13abbc5a7336524
1446b43ab728201
151e610a702e20e
hexe752db640e49

254343054102089 has 2 divisors, whose sum is σ = 254343054102090. Its totient is φ = 254343054102088.

The previous prime is 254343054102017. The next prime is 254343054102157. The reversal of 254343054102089 is 980201450343452.

254343054102089 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 135166968533689 + 119176085568400 = 11626133^2 + 10916780^2 .

It is a cyclic number.

It is not a de Polignac number, because 254343054102089 - 28 = 254343054101833 is a prime.

It is not a weakly prime, because it can be changed into another prime (254343054102289) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127171527051044 + 127171527051045.

It is an arithmetic number, because the mean of its divisors is an integer number (127171527051045).

Almost surely, 2254343054102089 is an apocalyptic number.

It is an amenable number.

254343054102089 is a deficient number, since it is larger than the sum of its proper divisors (1).

254343054102089 is an equidigital number, since it uses as much as digits as its factorization.

254343054102089 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4147200, while the sum is 50.

The spelling of 254343054102089 in words is "two hundred fifty-four trillion, three hundred forty-three billion, fifty-four million, one hundred two thousand, eighty-nine".