Base | Representation |
---|---|
bin | 1001011110011110… |
… | …0000000101111001 |
3 | 20120021110002112212 |
4 | 2113213200011321 |
5 | 20202142332211 |
6 | 1100224344505 |
7 | 120015134534 |
oct | 22747400571 |
9 | 6507402485 |
10 | 2543714681 |
11 | 1095951542 |
12 | 5aba75135 |
13 | 316cc6a21 |
14 | 1a1b8da1b |
15 | ed4b338b |
hex | 979e0179 |
2543714681 has 2 divisors, whose sum is σ = 2543714682. Its totient is φ = 2543714680.
The previous prime is 2543714659. The next prime is 2543714689. The reversal of 2543714681 is 1864173452.
2543714681 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2080819456 + 462895225 = 45616^2 + 21515^2 .
It is a cyclic number.
It is not a de Polignac number, because 2543714681 - 26 = 2543714617 is a prime.
It is a super-2 number, since 2×25437146812 = 12940968756669863522, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2543714689) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271857340 + 1271857341.
It is an arithmetic number, because the mean of its divisors is an integer number (1271857341).
Almost surely, 22543714681 is an apocalyptic number.
It is an amenable number.
2543714681 is a deficient number, since it is larger than the sum of its proper divisors (1).
2543714681 is an equidigital number, since it uses as much as digits as its factorization.
2543714681 is an evil number, because the sum of its binary digits is even.
The product of its digits is 161280, while the sum is 41.
The square root of 2543714681 is about 50435.2523637981. The cubic root of 2543714681 is about 1365.0738028051.
The spelling of 2543714681 in words is "two billion, five hundred forty-three million, seven hundred fourteen thousand, six hundred eighty-one".
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