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25437641137 is a prime number
BaseRepresentation
bin10111101100001100…
…111001100110110001
32102122210102001120221
4113230030321212301
5404044014004022
615404052533041
71560240245026
oct275414714661
972583361527
1025437641137
11a873981317
124b1b021181
1325250c6a7c
14133454954d
159dd31dcc7
hex5ec3399b1

25437641137 has 2 divisors, whose sum is σ = 25437641138. Its totient is φ = 25437641136.

The previous prime is 25437641113. The next prime is 25437641179. The reversal of 25437641137 is 73114673452.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22683070881 + 2754570256 = 150609^2 + 52484^2 .

It is a cyclic number.

It is not a de Polignac number, because 25437641137 - 215 = 25437608369 is a prime.

It is a super-2 number, since 2×254376411372 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25437641093 and 25437641102.

It is not a weakly prime, because it can be changed into another prime (25437641837) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12718820568 + 12718820569.

It is an arithmetic number, because the mean of its divisors is an integer number (12718820569).

Almost surely, 225437641137 is an apocalyptic number.

It is an amenable number.

25437641137 is a deficient number, since it is larger than the sum of its proper divisors (1).

25437641137 is an equidigital number, since it uses as much as digits as its factorization.

25437641137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 423360, while the sum is 43.

The spelling of 25437641137 in words is "twenty-five billion, four hundred thirty-seven million, six hundred forty-one thousand, one hundred thirty-seven".