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254430135325057 is a prime number
BaseRepresentation
bin111001110110011100100001…
…110101100001000110000001
31020100212021122120222112002111
4321312130201311201012001
5231322040404120400212
62301043331321415321
7104406653640011446
oct7166344165410601
91210767576875074
10254430135325057
117408423a45811a
122465232163a541
13abc78745421b3
1446b86acb239cd
151e634a200cea7
hexe76721d61181

254430135325057 has 2 divisors, whose sum is σ = 254430135325058. Its totient is φ = 254430135325056.

The previous prime is 254430135325013. The next prime is 254430135325081. The reversal of 254430135325057 is 750523531034452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 221577991166016 + 32852144159041 = 14885496^2 + 5731679^2 .

It is a cyclic number.

It is not a de Polignac number, because 254430135325057 - 231 = 254427987841409 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 254430135325057.

It is not a weakly prime, because it can be changed into another prime (254430135325097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127215067662528 + 127215067662529.

It is an arithmetic number, because the mean of its divisors is an integer number (127215067662529).

Almost surely, 2254430135325057 is an apocalyptic number.

It is an amenable number.

254430135325057 is a deficient number, since it is larger than the sum of its proper divisors (1).

254430135325057 is an equidigital number, since it uses as much as digits as its factorization.

254430135325057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7560000, while the sum is 49.

The spelling of 254430135325057 in words is "two hundred fifty-four trillion, four hundred thirty billion, one hundred thirty-five million, three hundred twenty-five thousand, fifty-seven".