Base | Representation |
---|---|
bin | 100101000001101011010… |
… | …101100000100111111001 |
3 | 100000020121002211112010212 |
4 | 211001223111200213321 |
5 | 313141433342034433 |
6 | 5224520245520505 |
7 | 351554064251006 |
oct | 45015325404771 |
9 | 10006532745125 |
10 | 2544421439993 |
11 | 8a10a062a664 |
12 | 351161713135 |
13 | 155c26793384 |
14 | 8b21757a8ad |
15 | 462bd868d48 |
hex | 2506b5609f9 |
2544421439993 has 2 divisors, whose sum is σ = 2544421439994. Its totient is φ = 2544421439992.
The previous prime is 2544421439971. The next prime is 2544421440019. The reversal of 2544421439993 is 3999341244452.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2298765404224 + 245656035769 = 1516168^2 + 495637^2 .
It is a cyclic number.
It is not a de Polignac number, because 2544421439993 - 228 = 2544153004537 is a prime.
It is not a weakly prime, because it can be changed into another prime (2544421439933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1272210719996 + 1272210719997.
It is an arithmetic number, because the mean of its divisors is an integer number (1272210719997).
Almost surely, 22544421439993 is an apocalyptic number.
It is an amenable number.
2544421439993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2544421439993 is an equidigital number, since it uses as much as digits as its factorization.
2544421439993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 33592320, while the sum is 59.
The spelling of 2544421439993 in words is "two trillion, five hundred forty-four billion, four hundred twenty-one million, four hundred thirty-nine thousand, nine hundred ninety-three".
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