Base | Representation |
---|---|
bin | 10111101100101001… |
… | …100010100110010001 |
3 | 2102200022112111112122 |
4 | 113230221202212101 |
5 | 404102424232243 |
6 | 15404521504025 |
7 | 1560361125041 |
oct | 275451424621 |
9 | 72608474478 |
10 | 25445149073 |
11 | a87813a123 |
12 | 4b21642015 |
13 | 2526825236 |
14 | 1335541721 |
15 | 9ddd03668 |
hex | 5eca62991 |
25445149073 has 2 divisors, whose sum is σ = 25445149074. Its totient is φ = 25445149072.
The previous prime is 25445149033. The next prime is 25445149099. The reversal of 25445149073 is 37094154452.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17012767489 + 8432381584 = 130433^2 + 91828^2 .
It is a cyclic number.
It is not a de Polignac number, because 25445149073 - 214 = 25445132689 is a prime.
It is a super-2 number, since 2×254451490732 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (25445149033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12722574536 + 12722574537.
It is an arithmetic number, because the mean of its divisors is an integer number (12722574537).
Almost surely, 225445149073 is an apocalyptic number.
It is an amenable number.
25445149073 is a deficient number, since it is larger than the sum of its proper divisors (1).
25445149073 is an equidigital number, since it uses as much as digits as its factorization.
25445149073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 604800, while the sum is 44.
The spelling of 25445149073 in words is "twenty-five billion, four hundred forty-five million, one hundred forty-nine thousand, seventy-three".
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