Base | Representation |
---|---|
bin | 100101000010001111110… |
… | …100011000010001101101 |
3 | 100000022011202120000011010 |
4 | 211002033310120101231 |
5 | 313144212034341140 |
6 | 5225101112415433 |
7 | 351605205626433 |
oct | 45021764302155 |
9 | 10008152500133 |
10 | 2545033512045 |
11 | 8a1385083432 |
12 | 3512b26a7579 |
13 | 155cc352799b |
14 | 8b274986d53 |
15 | 4630746d880 |
hex | 2508fd1846d |
2545033512045 has 32 divisors (see below), whose sum is σ = 4083199340544. Its totient is φ = 1353636864000.
The previous prime is 2545033512029. The next prime is 2545033512089. The reversal of 2545033512045 is 5402153305452.
It is not a de Polignac number, because 2545033512045 - 24 = 2545033512029 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2545033511994 and 2545033512012.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 55134675 + ... + 55180815.
It is an arithmetic number, because the mean of its divisors is an integer number (127599979392).
Almost surely, 22545033512045 is an apocalyptic number.
It is an amenable number.
2545033512045 is a deficient number, since it is larger than the sum of its proper divisors (1538165828499).
2545033512045 is a wasteful number, since it uses less digits than its factorization.
2545033512045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56133.
The product of its (nonzero) digits is 360000, while the sum is 39.
Adding to 2545033512045 its reverse (5402153305452), we get a palindrome (7947186817497).
The spelling of 2545033512045 in words is "two trillion, five hundred forty-five billion, thirty-three million, five hundred twelve thousand, forty-five".
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