Base | Representation |
---|---|
bin | 1001011111110101… |
… | …0110011000100011 |
3 | 20120200020002001212 |
4 | 2113331112120203 |
5 | 20210124121313 |
6 | 1100551220335 |
7 | 120114620516 |
oct | 22775263043 |
9 | 6520202055 |
10 | 2549442083 |
11 | 1099103631 |
12 | 5b19776ab |
13 | 318250916 |
14 | 1a2840d7d |
15 | edc453a8 |
hex | 97f56623 |
2549442083 has 2 divisors, whose sum is σ = 2549442084. Its totient is φ = 2549442082.
The previous prime is 2549442037. The next prime is 2549442109. The reversal of 2549442083 is 3802449452.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2549442083 - 28 = 2549441827 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2549442083.
It is not a weakly prime, because it can be changed into another prime (2549442013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1274721041 + 1274721042.
It is an arithmetic number, because the mean of its divisors is an integer number (1274721042).
Almost surely, 22549442083 is an apocalyptic number.
2549442083 is a deficient number, since it is larger than the sum of its proper divisors (1).
2549442083 is an equidigital number, since it uses as much as digits as its factorization.
2549442083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 276480, while the sum is 41.
The square root of 2549442083 is about 50492.0001881486. Note that the first 3 decimals coincide. The cubic root of 2549442083 is about 1366.0975635709.
The spelling of 2549442083 in words is "two billion, five hundred forty-nine million, four hundred forty-two thousand, eighty-three".
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