255001405413 has 4 divisors (see below), whose sum is σ = 340001873888. Its totient is φ = 170000936940.

The previous prime is 255001405411. The next prime is 255001405423. The reversal of 255001405413 is 314504100552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 255001405413 - 2¹ = 255001405411 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255001405411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42500234233 + ... + 42500234238.

It is an arithmetic number, because the mean of its divisors is an integer number (85000468472).

Almost surely, 2^255001405413 is an apocalyptic number.

It is an amenable number.

255001405413 is a deficient number, since it is larger than the sum of its proper divisors (85000468475).

255001405413 is an equidigital number, since it uses as much as digits as its factorization.

255001405413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85000468474.

The product of its (nonzero) digits is 12000, while the sum is 30.

Adding to 255001405413 its reverse (314504100552), we get a palindrome (569505505965).

The spelling of 255001405413 in words is "two hundred fifty-five billion, one million, four hundred five thousand, four hundred thirteen".