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255024131 is a prime number
BaseRepresentation
bin11110011001101…
…01110000000011
3122202212120100012
433030311300003
51010241233011
641150015135
76214445405
oct1714656003
9582776305
10255024131
11120a5544a
12714a74ab
1340ab146b
1425c26b75
15175c7a8b
hexf335c03

255024131 has 2 divisors, whose sum is σ = 255024132. Its totient is φ = 255024130.

The previous prime is 255024109. The next prime is 255024151. The reversal of 255024131 is 131420552.

255024131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 255024131 - 26 = 255024067 is a prime.

It is a super-2 number, since 2×2550241312 = 130074614784610322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 255024097 and 255024106.

It is not a weakly prime, because it can be changed into another prime (255024151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127512065 + 127512066.

It is an arithmetic number, because the mean of its divisors is an integer number (127512066).

Almost surely, 2255024131 is an apocalyptic number.

255024131 is a deficient number, since it is larger than the sum of its proper divisors (1).

255024131 is an equidigital number, since it uses as much as digits as its factorization.

255024131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 255024131 is about 15969.4749757154. The cubic root of 255024131 is about 634.1525728527.

Adding to 255024131 its reverse (131420552), we get a palindrome (386444683).

The spelling of 255024131 in words is "two hundred fifty-five million, twenty-four thousand, one hundred thirty-one".