Base | Representation |
---|---|
bin | 111001111111001011100000… |
… | …011010000101001000101011 |
3 | 1020102222122212101212021201002 |
4 | 321333023200122011020223 |
5 | 231411404110224110201 |
6 | 2302223152333345215 |
7 | 104501222253245450 |
oct | 7177134032051053 |
9 | 1212878771767632 |
10 | 255030333035051 |
11 | 7429583640a102 |
12 | 2472a70663820b |
13 | ac3c346134562 |
14 | 46d9769351827 |
15 | 1e73dce3d176b |
hex | e7f2e068522b |
255030333035051 has 16 divisors (see below), whose sum is σ = 294469845003264. Its totient is φ = 216342500914944.
The previous prime is 255030333035039. The next prime is 255030333035059. The reversal of 255030333035051 is 150530333030552.
255030333035051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 255030333035051 - 234 = 255013153165867 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 255030333034996 and 255030333035014.
It is not an unprimeable number, because it can be changed into a prime (255030333035059) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 116849486 + ... + 119012028.
It is an arithmetic number, because the mean of its divisors is an integer number (18404365312704).
Almost surely, 2255030333035051 is an apocalyptic number.
255030333035051 is a deficient number, since it is larger than the sum of its proper divisors (39439511968213).
255030333035051 is a wasteful number, since it uses less digits than its factorization.
255030333035051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2336330.
The product of its (nonzero) digits is 303750, while the sum is 38.
The spelling of 255030333035051 in words is "two hundred fifty-five trillion, thirty billion, three hundred thirty-three million, thirty-five thousand, fifty-one".
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