Base | Representation |
---|---|
bin | 111001111111001011100000… |
… | …100001101001101111100100 |
3 | 1020102222122212112121010112212 |
4 | 321333023200201221233210 |
5 | 231411404111231120004 |
6 | 2302223152444102552 |
7 | 104501222306153465 |
oct | 7177134041515744 |
9 | 1212878775533485 |
10 | 255030335020004 |
11 | 74295837545465 |
12 | 2472a707234a58 |
13 | ac3c34667ab9b |
14 | 46d976970ad6c |
15 | 1e73dce67496e |
hex | e7f2e0869be4 |
255030335020004 has 12 divisors (see below), whose sum is σ = 446303234208300. Its totient is φ = 127515125246208.
The previous prime is 255030335019979. The next prime is 255030335020093. The reversal of 255030335020004 is 400020533030552.
It can be written as a sum of positive squares in 2 ways, for example, as 117750494664100 + 137279840355904 = 10851290^2 + 11716648^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5842352 + ... + 23327960.
It is an arithmetic number, because the mean of its divisors is an integer number (37191936184025).
Almost surely, 2255030335020004 is an apocalyptic number.
It is an amenable number.
255030335020004 is a deficient number, since it is larger than the sum of its proper divisors (191272899188296).
255030335020004 is a wasteful number, since it uses less digits than its factorization.
255030335020004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21131902 (or 21131900 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 32.
Adding to 255030335020004 its reverse (400020533030552), we get a palindrome (655050868050556).
The spelling of 255030335020004 in words is "two hundred fifty-five trillion, thirty billion, three hundred thirty-five million, twenty thousand, four".
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