Base | Representation |
---|---|
bin | 111001111111001100010101… |
… | …111100000011010111001111 |
3 | 1020102222202011222210101200002 |
4 | 321333030111330003113033 |
5 | 231411412430132230020 |
6 | 2302223421414554515 |
7 | 104501253440043302 |
oct | 7177142574032717 |
9 | 1212882158711602 |
10 | 255031231133135 |
11 | 74296157362526 |
12 | 2472a917368a3b |
13 | ac3c45a213342 |
14 | 46d9812734b39 |
15 | 1e73e33184975 |
hex | e7f315f035cf |
255031231133135 has 16 divisors (see below), whose sum is σ = 310026880035840. Its totient is φ = 201367308299040.
The previous prime is 255031231133131. The next prime is 255031231133251. The reversal of 255031231133135 is 531331132130552.
It is not a de Polignac number, because 255031231133135 - 22 = 255031231133131 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255031231133131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 119262371 + ... + 121381940.
It is an arithmetic number, because the mean of its divisors is an integer number (19376680002240).
Almost surely, 2255031231133135 is an apocalyptic number.
255031231133135 is a deficient number, since it is larger than the sum of its proper divisors (54995648902705).
255031231133135 is a wasteful number, since it uses less digits than its factorization.
255031231133135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 240647078.
The product of its (nonzero) digits is 121500, while the sum is 38.
Adding to 255031231133135 its reverse (531331132130552), we get a palindrome (786362363263687).
The spelling of 255031231133135 in words is "two hundred fifty-five trillion, thirty-one billion, two hundred thirty-one million, one hundred thirty-three thousand, one hundred thirty-five".
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