Base | Representation |
---|---|
bin | 100101000111001100001… |
… | …011101100101010110111 |
3 | 100000210212122221202201201 |
4 | 211013030023230222313 |
5 | 313241044323201033 |
6 | 5231335515233331 |
7 | 352153555506565 |
oct | 45071413545267 |
9 | 10023778852651 |
10 | 2550341225143 |
11 | 8a3659152888 |
12 | 352334148847 |
13 | 15665b05501a |
14 | 8b619868a35 |
15 | 4651840947d |
hex | 251cc2ecab7 |
2550341225143 has 8 divisors (see below), whose sum is σ = 2639905638480. Its totient is φ = 2460884919360.
The previous prime is 2550341225129. The next prime is 2550341225153. The reversal of 2550341225143 is 3415221430552.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2550341225143 - 225 = 2550307670711 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2550341225153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26978878 + ... + 27073243.
It is an arithmetic number, because the mean of its divisors is an integer number (329988204810).
Almost surely, 22550341225143 is an apocalyptic number.
2550341225143 is a deficient number, since it is larger than the sum of its proper divisors (89564413337).
2550341225143 is a wasteful number, since it uses less digits than its factorization.
2550341225143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54053777.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 2550341225143 its reverse (3415221430552), we get a palindrome (5965562655695).
The spelling of 2550341225143 in words is "two trillion, five hundred fifty billion, three hundred forty-one million, two hundred twenty-five thousand, one hundred forty-three".
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