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2550341225143 = 29162754052121
BaseRepresentation
bin100101000111001100001…
…011101100101010110111
3100000210212122221202201201
4211013030023230222313
5313241044323201033
65231335515233331
7352153555506565
oct45071413545267
910023778852651
102550341225143
118a3659152888
12352334148847
1315665b05501a
148b619868a35
154651840947d
hex251cc2ecab7

2550341225143 has 8 divisors (see below), whose sum is σ = 2639905638480. Its totient is φ = 2460884919360.

The previous prime is 2550341225129. The next prime is 2550341225153. The reversal of 2550341225143 is 3415221430552.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2550341225143 - 225 = 2550307670711 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2550341225153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26978878 + ... + 27073243.

It is an arithmetic number, because the mean of its divisors is an integer number (329988204810).

Almost surely, 22550341225143 is an apocalyptic number.

2550341225143 is a deficient number, since it is larger than the sum of its proper divisors (89564413337).

2550341225143 is a wasteful number, since it uses less digits than its factorization.

2550341225143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54053777.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 2550341225143 its reverse (3415221430552), we get a palindrome (5965562655695).

The spelling of 2550341225143 in words is "two trillion, five hundred fifty billion, three hundred forty-one million, two hundred twenty-five thousand, one hundred forty-three".

Divisors: 1 29 1627 47183 54052121 1567511509 87942800867 2550341225143