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2550351407 = 17150020671
BaseRepresentation
bin1001100000000011…
…0100011000101111
320120201221021102112
42120000310120233
520210342221112
61101022514235
7120125425562
oct23000643057
96521837375
102550351407
11109967483a
125b213597b
133184ab796
141a29da4d9
15edd74a22
hex9803462f

2550351407 has 4 divisors (see below), whose sum is σ = 2700372096. Its totient is φ = 2400330720.

The previous prime is 2550351347. The next prime is 2550351409. The reversal of 2550351407 is 7041530552.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2550351407 - 28 = 2550351151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2550351409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75010319 + ... + 75010352.

It is an arithmetic number, because the mean of its divisors is an integer number (675093024).

Almost surely, 22550351407 is an apocalyptic number.

2550351407 is a deficient number, since it is larger than the sum of its proper divisors (150020689).

2550351407 is a wasteful number, since it uses less digits than its factorization.

2550351407 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 150020688.

The product of its (nonzero) digits is 21000, while the sum is 32.

The square root of 2550351407 is about 50501.0040197222. The cubic root of 2550351407 is about 1366.2599621924.

Adding to 2550351407 its reverse (7041530552), we get a palindrome (9591881959).

The spelling of 2550351407 in words is "two billion, five hundred fifty million, three hundred fifty-one thousand, four hundred seven".

Divisors: 1 17 150020671 2550351407