255040400137 has 2 divisors, whose sum is σ = 255040400138. Its totient is φ = 255040400136.

The previous prime is 255040400117. The next prime is 255040400191. The reversal of 255040400137 is 731004040552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 138018937081 + 117021463056 = 371509^2 + 342084^2 .

It is a cyclic number.

It is not a de Polignac number, because 255040400137 - 2²³ = 255032011529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 255040400099 and 255040400108.

It is not a weakly prime, because it can be changed into another prime (255040400117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127520200068 + 127520200069.

It is an arithmetic number, because the mean of its divisors is an integer number (127520200069).

Almost surely, 2^255040400137 is an apocalyptic number.

It is an amenable number.

255040400137 is a deficient number, since it is larger than the sum of its proper divisors (1).

255040400137 is an equidigital number, since it uses as much as digits as its factorization.

255040400137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16800, while the sum is 31.

Adding to 255040400137 its reverse (731004040552), we get a palindrome (986044440689).

The spelling of 255040400137 in words is "two hundred fifty-five billion, forty million, four hundred thousand, one hundred thirty-seven".