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2550449040 = 2435195361173
BaseRepresentation
bin1001100000000100…
…1100001110010000
320120202010020100120
42120001030032100
520210403332130
61101024550240
7120126313326
oct23001141620
96522106316
102550449040
111099731127
125b2182380
13318514059
141a2a23d16
15edd93910
hex9804c390

2550449040 has 320 divisors, whose sum is σ = 8668373760. Its totient is φ = 618209280.

The previous prime is 2550449039. The next prime is 2550449113. The reversal of 2550449040 is 409440552.

It is a junction number, because it is equal to n+sod(n) for n = 2550448992 and 2550449010.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 14742394 + ... + 14742566.

It is an arithmetic number, because the mean of its divisors is an integer number (27088668).

Almost surely, 22550449040 is an apocalyptic number.

2550449040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2550449040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4334186880).

2550449040 is an abundant number, since it is smaller than the sum of its proper divisors (6117924720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2550449040 is a wasteful number, since it uses less digits than its factorization.

2550449040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 322 (or 316 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 33.

The square root of 2550449040 is about 50501.9706546190. The cubic root of 2550449040 is about 1366.2773964378.

Adding to 2550449040 its reverse (409440552), we get a palindrome (2959889592).

The spelling of 2550449040 in words is "two billion, five hundred fifty million, four hundred forty-nine thousand, forty".