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255100427 is a prime number
BaseRepresentation
bin11110011010010…
…00011000001011
3122210000102222222
433031020120023
51010301203202
641151404255
76215214011
oct1715103013
9583012888
10255100427
11120aa77aa
127152368b
1340b0a0ca
1425c468b1
15175e04a2
hexf34860b

255100427 has 2 divisors, whose sum is σ = 255100428. Its totient is φ = 255100426.

The previous prime is 255100393. The next prime is 255100451. The reversal of 255100427 is 724001552.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 255100427 - 28 = 255100171 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 255100396 and 255100405.

It is not a weakly prime, because it can be changed into another prime (255100927) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127550213 + 127550214.

It is an arithmetic number, because the mean of its divisors is an integer number (127550214).

Almost surely, 2255100427 is an apocalyptic number.

255100427 is a deficient number, since it is larger than the sum of its proper divisors (1).

255100427 is an equidigital number, since it uses as much as digits as its factorization.

255100427 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2800, while the sum is 26.

The square root of 255100427 is about 15971.8636044765. The cubic root of 255100427 is about 634.2158067127.

Adding to 255100427 its reverse (724001552), we get a palindrome (979101979).

The spelling of 255100427 in words is "two hundred fifty-five million, one hundred thousand, four hundred twenty-seven".