Base | Representation |
---|---|
bin | 1110110110010101100… |
… | …1101011001111100001 |
3 | 220101110122202011101110 |
4 | 3231211121223033201 |
5 | 13134423200100001 |
6 | 313105430253533 |
7 | 24300502525605 |
oct | 3554531531741 |
9 | 811418664343 |
10 | 255104300001 |
11 | 992097aa401 |
12 | 41535ab72a9 |
13 | 1b096708555 |
14 | c4c06a3505 |
15 | 6980ec43d6 |
hex | 3b6566b3e1 |
255104300001 has 32 divisors (see below), whose sum is σ = 345007060992. Its totient is φ = 167654009600.
The previous prime is 255104299999. The next prime is 255104300023. The reversal of 255104300001 is 100003401552.
It is a cyclic number.
It is not a de Polignac number, because 255104300001 - 21 = 255104299999 is a prime.
It is a super-3 number, since 3×2551043000013 (a number of 35 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (255104300401) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 66241726 + ... + 66245576.
It is an arithmetic number, because the mean of its divisors is an integer number (10781470656).
Almost surely, 2255104300001 is an apocalyptic number.
It is an amenable number.
255104300001 is a deficient number, since it is larger than the sum of its proper divisors (89902760991).
255104300001 is a wasteful number, since it uses less digits than its factorization.
255104300001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4973.
The product of its (nonzero) digits is 600, while the sum is 21.
Adding to 255104300001 its reverse (100003401552), we get a palindrome (355107701553).
The spelling of 255104300001 in words is "two hundred fifty-five billion, one hundred four million, three hundred thousand, one".
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