Base | Representation |
---|---|
bin | 111010000000011001101111… |
… | …010111000101101011001111 |
3 | 1020110021200200200211102122100 |
4 | 322000121233113011223033 |
5 | 231414243124424140333 |
6 | 2302325524035450143 |
7 | 104510255030601246 |
oct | 7200315727055317 |
9 | 1213250620742570 |
10 | 255114335771343 |
11 | 743184227a9204 |
12 | 24742a4aa56953 |
13 | ac47242608389 |
14 | 46dd85795395d |
15 | 1e76198eb6213 |
hex | e8066f5c5acf |
255114335771343 has 48 divisors (see below), whose sum is σ = 371596695808000. Its totient is φ = 168650346369600.
The previous prime is 255114335771329. The next prime is 255114335771377. The reversal of 255114335771343 is 343177533411552.
255114335771343 is a `hidden beast` number, since 2 + 5 + 5 + 1 + 1 + 4 + 33 + 577 + 1 + 34 + 3 = 666.
It is not a de Polignac number, because 255114335771343 - 216 = 255114335705807 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 255114335771343.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255114335771303) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 9196941168 + ... + 9196968906.
Almost surely, 2255114335771343 is an apocalyptic number.
255114335771343 is a deficient number, since it is larger than the sum of its proper divisors (116482360036657).
255114335771343 is a wasteful number, since it uses less digits than its factorization.
255114335771343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39652 (or 39649 counting only the distinct ones).
The product of its digits is 15876000, while the sum is 54.
The spelling of 255114335771343 in words is "two hundred fifty-five trillion, one hundred fourteen billion, three hundred thirty-five million, seven hundred seventy-one thousand, three hundred forty-three".
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