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255122520012907 is a prime number
BaseRepresentation
bin111010000000100001010111…
…001011011111100001101011
31020110022110211001220222110021
4322000201113023133201223
5231414411410110403112
62302333400120301311
7104510664606523651
oct7200412713374153
91213273731828407
10255122520012907
1174320942576008
1224744553911837
13ac47c48078b71
1446dddd289add1
151e764c7756907
hexe808572df86b

255122520012907 has 2 divisors, whose sum is σ = 255122520012908. Its totient is φ = 255122520012906.

The previous prime is 255122520012803. The next prime is 255122520012923. The reversal of 255122520012907 is 709210025221552.

255122520012907 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 255122520012907 - 235 = 255088160274539 is a prime.

It is a super-2 number, since 2×2551225200129072 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (255122520018907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127561260006453 + 127561260006454.

It is an arithmetic number, because the mean of its divisors is an integer number (127561260006454).

Almost surely, 2255122520012907 is an apocalyptic number.

255122520012907 is a deficient number, since it is larger than the sum of its proper divisors (1).

255122520012907 is an equidigital number, since it uses as much as digits as its factorization.

255122520012907 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252000, while the sum is 43.

The spelling of 255122520012907 in words is "two hundred fifty-five trillion, one hundred twenty-two billion, five hundred twenty million, twelve thousand, nine hundred seven".