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255130031551 = 269948438779
BaseRepresentation
bin1110110110011011101…
…1110101010110111111
3220101112110011110102211
43231212323311112333
513140001242002201
6313112150001251
724301234325653
oct3554673652677
9811473143384
10255130031551
119922228494a
1241542646227
131b09bb47715
14c4c3c80a63
1569833a8651
hex3b66ef55bf

255130031551 has 4 divisors (see below), whose sum is σ = 256078470600. Its totient is φ = 254181592504.

The previous prime is 255130031549. The next prime is 255130031561. The reversal of 255130031551 is 155130031552.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 255130031551 - 21 = 255130031549 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255130031501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 474219121 + ... + 474219658.

It is an arithmetic number, because the mean of its divisors is an integer number (64019617650).

Almost surely, 2255130031551 is an apocalyptic number.

255130031551 is a deficient number, since it is larger than the sum of its proper divisors (948439049).

255130031551 is an equidigital number, since it uses as much as digits as its factorization.

255130031551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 948439048.

The product of its (nonzero) digits is 11250, while the sum is 31.

Subtracting from 255130031551 its reverse (155130031552), we obtain a palindrome (99999999999).

The spelling of 255130031551 in words is "two hundred fifty-five billion, one hundred thirty million, thirty-one thousand, five hundred fifty-one".

Divisors: 1 269 948438779 255130031551