Base | Representation |
---|---|
bin | 1110110110011100010… |
… | …1101011100111101111 |
3 | 220101112122000121122212 |
4 | 3231213011223213233 |
5 | 13140002422104403 |
6 | 313112321201035 |
7 | 24301265300234 |
oct | 3554705534757 |
9 | 811478017585 |
10 | 255132613103 |
11 | 99223788465 |
12 | 4154349017b |
13 | 1b09c53c774 |
14 | c4c435378b |
15 | 69837184d8 |
hex | 3b6716b9ef |
255132613103 has 4 divisors (see below), whose sum is σ = 255141932640. Its totient is φ = 255123293568.
The previous prime is 255132613093. The next prime is 255132613121. The reversal of 255132613103 is 301316231552.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255132613103 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 255132613103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255132613163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4618583 + ... + 4673496.
It is an arithmetic number, because the mean of its divisors is an integer number (63785483160).
Almost surely, 2255132613103 is an apocalyptic number.
255132613103 is a deficient number, since it is larger than the sum of its proper divisors (9319537).
255132613103 is an equidigital number, since it uses as much as digits as its factorization.
255132613103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9319536.
The product of its (nonzero) digits is 16200, while the sum is 32.
Adding to 255132613103 its reverse (301316231552), we get a palindrome (556448844655).
The spelling of 255132613103 in words is "two hundred fifty-five billion, one hundred thirty-two million, six hundred thirteen thousand, one hundred three".
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