Base | Representation |
---|---|
bin | 111010000000110100100010… |
… | …000010001010011010010001 |
3 | 1020110101102221112211210022001 |
4 | 322000310202002022122101 |
5 | 231420231033410224103 |
6 | 2302351042401514001 |
7 | 104512323643031203 |
oct | 7200644202123221 |
9 | 1213342845753261 |
10 | 255143103211153 |
11 | 74329645217553 |
12 | 24748539042901 |
13 | ac49b78518901 |
14 | 4700dc63d4773 |
15 | 1e76cce7c201d |
hex | e80d2208a691 |
255143103211153 has 2 divisors, whose sum is σ = 255143103211154. Its totient is φ = 255143103211152.
The previous prime is 255143103211097. The next prime is 255143103211169. The reversal of 255143103211153 is 351112301341552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 183793794501249 + 71349308709904 = 13557057^2 + 8446852^2 .
It is a cyclic number.
It is not a de Polignac number, because 255143103211153 - 213 = 255143103202961 is a prime.
It is not a weakly prime, because it can be changed into another prime (255143103211853) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127571551605576 + 127571551605577.
It is an arithmetic number, because the mean of its divisors is an integer number (127571551605577).
Almost surely, 2255143103211153 is an apocalyptic number.
It is an amenable number.
255143103211153 is a deficient number, since it is larger than the sum of its proper divisors (1).
255143103211153 is an equidigital number, since it uses as much as digits as its factorization.
255143103211153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 37.
The spelling of 255143103211153 in words is "two hundred fifty-five trillion, one hundred forty-three billion, one hundred three million, two hundred eleven thousand, one hundred fifty-three".
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