Base | Representation |
---|---|
bin | 111010000000110110100010… |
… | …000011110000010011000111 |
3 | 1020110101122111020111110112021 |
4 | 322000312202003300103013 |
5 | 231420244433241042020 |
6 | 2302352035450504011 |
7 | 104512431113631166 |
oct | 7200664203602307 |
9 | 1213348436443467 |
10 | 255145251112135 |
11 | 7432a5476a232a |
12 | 24748a38435007 |
13 | ac4a12b508637 |
14 | 470114b78d3dd |
15 | 1e76da814c1aa |
hex | e80da20f04c7 |
255145251112135 has 16 divisors (see below), whose sum is σ = 316809081613440. Its totient is φ = 197029771626240.
The previous prime is 255145251112127. The next prime is 255145251112223. The reversal of 255145251112135 is 531211152541552.
It is a happy number.
It is not a de Polignac number, because 255145251112135 - 23 = 255145251112127 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 255145251112091 and 255145251112100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 213417822 + ... + 214610011.
It is an arithmetic number, because the mean of its divisors is an integer number (19800567600840).
Almost surely, 2255145251112135 is an apocalyptic number.
255145251112135 is a deficient number, since it is larger than the sum of its proper divisors (61663830501305).
255145251112135 is a wasteful number, since it uses less digits than its factorization.
255145251112135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 428031978.
The product of its digits is 300000, while the sum is 43.
The spelling of 255145251112135 in words is "two hundred fifty-five trillion, one hundred forty-five billion, two hundred fifty-one million, one hundred twelve thousand, one hundred thirty-five".
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