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255145251112135 = 5294111428027833
BaseRepresentation
bin111010000000110110100010…
…000011110000010011000111
31020110101122111020111110112021
4322000312202003300103013
5231420244433241042020
62302352035450504011
7104512431113631166
oct7200664203602307
91213348436443467
10255145251112135
117432a5476a232a
1224748a38435007
13ac4a12b508637
14470114b78d3dd
151e76da814c1aa
hexe80da20f04c7

255145251112135 has 16 divisors (see below), whose sum is σ = 316809081613440. Its totient is φ = 197029771626240.

The previous prime is 255145251112127. The next prime is 255145251112223. The reversal of 255145251112135 is 531211152541552.

It is a happy number.

It is not a de Polignac number, because 255145251112135 - 23 = 255145251112127 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 255145251112091 and 255145251112100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 213417822 + ... + 214610011.

It is an arithmetic number, because the mean of its divisors is an integer number (19800567600840).

Almost surely, 2255145251112135 is an apocalyptic number.

255145251112135 is a deficient number, since it is larger than the sum of its proper divisors (61663830501305).

255145251112135 is a wasteful number, since it uses less digits than its factorization.

255145251112135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 428031978.

The product of its digits is 300000, while the sum is 43.

The spelling of 255145251112135 in words is "two hundred fifty-five trillion, one hundred forty-five billion, two hundred fifty-one million, one hundred twelve thousand, one hundred thirty-five".

Divisors: 1 5 29 145 4111 20555 119219 596095 428027833 2140139165 12412807157 62064035785 1759622421463 8798112107315 51029050222427 255145251112135