Base | Representation |
---|---|
bin | 111010000010010001001001… |
… | …100001100111000111001011 |
3 | 1020110201221122011112211021112 |
4 | 322002101021201213013023 |
5 | 231423343220300430121 |
6 | 2302504450404000535 |
7 | 104522444221642211 |
oct | 7202211141470713 |
9 | 1213657564484245 |
10 | 255242550014411 |
11 | 74367837361763 |
12 | 2476387169014b |
13 | ac56366538aab |
14 | 4705b3bbb2cb1 |
15 | 1e796a018675b |
hex | e824498671cb |
255242550014411 has 2 divisors, whose sum is σ = 255242550014412. Its totient is φ = 255242550014410.
The previous prime is 255242550014401. The next prime is 255242550014477. The reversal of 255242550014411 is 114410055242552.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255242550014411 is a prime.
It is not a weakly prime, because it can be changed into another prime (255242550014401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127621275007205 + 127621275007206.
It is an arithmetic number, because the mean of its divisors is an integer number (127621275007206).
Almost surely, 2255242550014411 is an apocalyptic number.
255242550014411 is a deficient number, since it is larger than the sum of its proper divisors (1).
255242550014411 is an equidigital number, since it uses as much as digits as its factorization.
255242550014411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 320000, while the sum is 41.
The spelling of 255242550014411 in words is "two hundred fifty-five trillion, two hundred forty-two billion, five hundred fifty million, fourteen thousand, four hundred eleven".
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