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25530113000027 is a prime number
BaseRepresentation
bin1011100111000001100010…
…10100010000001001011011
310100101122200110201020120202
411303200301110100021123
511321241132412000102
6130144212204012415
75243326666650416
oct563406124201133
9110348613636522
1025530113000027
118153295246679
122a43aa723110b
13113263010387c
14643942288b7d
152e416bbd5e02
hex17383151025b

25530113000027 has 2 divisors, whose sum is σ = 25530113000028. Its totient is φ = 25530113000026.

The previous prime is 25530112999931. The next prime is 25530113000107. The reversal of 25530113000027 is 72000031103552.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 25530113000027 - 28 = 25530112999771 is a prime.

It is a super-2 number, since 2×255301130000272 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (25530113000927) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12765056500013 + 12765056500014.

It is an arithmetic number, because the mean of its divisors is an integer number (12765056500014).

Almost surely, 225530113000027 is an apocalyptic number.

25530113000027 is a deficient number, since it is larger than the sum of its proper divisors (1).

25530113000027 is an equidigital number, since it uses as much as digits as its factorization.

25530113000027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6300, while the sum is 29.

Adding to 25530113000027 its reverse (72000031103552), we get a palindrome (97530144103579).

The spelling of 25530113000027 in words is "twenty-five trillion, five hundred thirty billion, one hundred thirteen million, twenty-seven", and thus it is an aban number.