Base | Representation |
---|---|
bin | 100101001001110000101… |
… | …110000100011001001001 |
3 | 100001002000001021100110121 |
4 | 211021300232010121021 |
5 | 313312223013324013 |
6 | 5232513445543241 |
7 | 352312145241343 |
oct | 45116056043111 |
9 | 10032001240417 |
10 | 2553101698633 |
11 | 8a4845393432 |
12 | 352984714b21 |
13 | 1569aac230a5 |
14 | 8b7dc320293 |
15 | 4662a93758d |
hex | 25270b84649 |
2553101698633 has 2 divisors, whose sum is σ = 2553101698634. Its totient is φ = 2553101698632.
The previous prime is 2553101698613. The next prime is 2553101698691. The reversal of 2553101698633 is 3368961013552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1630708568064 + 922393130569 = 1276992^2 + 960413^2 .
It is a cyclic number.
It is not a de Polignac number, because 2553101698633 - 217 = 2553101567561 is a prime.
It is not a weakly prime, because it can be changed into another prime (2553101698613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1276550849316 + 1276550849317.
It is an arithmetic number, because the mean of its divisors is an integer number (1276550849317).
Almost surely, 22553101698633 is an apocalyptic number.
It is an amenable number.
2553101698633 is a deficient number, since it is larger than the sum of its proper divisors (1).
2553101698633 is an equidigital number, since it uses as much as digits as its factorization.
2553101698633 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3499200, while the sum is 52.
The spelling of 2553101698633 in words is "two trillion, five hundred fifty-three billion, one hundred one million, six hundred ninety-eight thousand, six hundred thirty-three".
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