Base | Representation |
---|---|
bin | 1011100111000011101001… |
… | …01001000111000000101001 |
3 | 10100101202121012010212122012 |
4 | 11303201310221013000221 |
5 | 11321300441042303342 |
6 | 130144520234005305 |
7 | 5243366663621156 |
oct | 563416451070051 |
9 | 110352535125565 |
10 | 25531242541097 |
11 | 81538148a8597 |
12 | 2a44161576835 |
13 | 1132780128677 |
14 | 643a0c2b722d |
15 | 2e41d5e54b82 |
hex | 173874a47029 |
25531242541097 has 2 divisors, whose sum is σ = 25531242541098. Its totient is φ = 25531242541096.
The previous prime is 25531242541093. The next prime is 25531242541229. The reversal of 25531242541097 is 79014524213552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24290467103296 + 1240775437801 = 4928536^2 + 1113901^2 .
It is a cyclic number.
It is not a de Polignac number, because 25531242541097 - 22 = 25531242541093 is a prime.
It is not a weakly prime, because it can be changed into another prime (25531242541093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12765621270548 + 12765621270549.
It is an arithmetic number, because the mean of its divisors is an integer number (12765621270549).
Almost surely, 225531242541097 is an apocalyptic number.
It is an amenable number.
25531242541097 is a deficient number, since it is larger than the sum of its proper divisors (1).
25531242541097 is an equidigital number, since it uses as much as digits as its factorization.
25531242541097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024000, while the sum is 50.
The spelling of 25531242541097 in words is "twenty-five trillion, five hundred thirty-one billion, two hundred forty-two million, five hundred forty-one thousand, ninety-seven".
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