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255315305141089 is a prime number
BaseRepresentation
bin111010000011010100111010…
…000100011001001101100001
31020110222220102121011012102221
4322003110322010121031201
5231431041221104003324
62303002122034511041
7104530631162214154
oct7203247204311541
91213886377135387
10255315305141089
1174395681772226
1224775997135481
13ac6018c6cb8cb
14470948068bc9b
151e7b50c5bb0e4
hexe8353a119361

255315305141089 has 2 divisors, whose sum is σ = 255315305141090. Its totient is φ = 255315305141088.

The previous prime is 255315305141053. The next prime is 255315305141093. The reversal of 255315305141089 is 980141503513552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 245525865640225 + 9789439500864 = 15669265^2 + 3128808^2 .

It is a cyclic number.

It is not a de Polignac number, because 255315305141089 - 221 = 255315303043937 is a prime.

It is a super-2 number, since 2×2553153051410892 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (255315305141189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127657652570544 + 127657652570545.

It is an arithmetic number, because the mean of its divisors is an integer number (127657652570545).

Almost surely, 2255315305141089 is an apocalyptic number.

It is an amenable number.

255315305141089 is a deficient number, since it is larger than the sum of its proper divisors (1).

255315305141089 is an equidigital number, since it uses as much as digits as its factorization.

255315305141089 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240000, while the sum is 52.

The spelling of 255315305141089 in words is "two hundred fifty-five trillion, three hundred fifteen billion, three hundred five million, one hundred forty-one thousand, eighty-nine".