Base | Representation |
---|---|
bin | 1110110111001110001… |
… | …1100011000101010111 |
3 | 220102002012120211200022 |
4 | 3231303203203011113 |
5 | 13140414443102142 |
6 | 313145152135355 |
7 | 24306415140311 |
oct | 3556343430527 |
9 | 812065524608 |
10 | 255341769047 |
11 | 99320854412 |
12 | 415a153755b |
13 | 1b103981391 |
14 | c50403a7b1 |
15 | 6996c806d2 |
hex | 3b738e3157 |
255341769047 has 4 divisors (see below), whose sum is σ = 255347676720. Its totient is φ = 255335861376.
The previous prime is 255341769017. The next prime is 255341769073. The reversal of 255341769047 is 740967143552.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 255341769047 - 216 = 255341703511 is a prime.
It is a super-4 number, since 4×2553417690474 (a number of 47 digits) contains 4444 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 255341769047.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255341769017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2888522 + ... + 2975607.
It is an arithmetic number, because the mean of its divisors is an integer number (63836919180).
Almost surely, 2255341769047 is an apocalyptic number.
255341769047 is a deficient number, since it is larger than the sum of its proper divisors (5907673).
255341769047 is an equidigital number, since it uses as much as digits as its factorization.
255341769047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5907672.
The product of its (nonzero) digits is 6350400, while the sum is 53.
The spelling of 255341769047 in words is "two hundred fifty-five billion, three hundred forty-one million, seven hundred sixty-nine thousand, forty-seven".
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