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25534214303 = 1310127171761
BaseRepresentation
bin10111110001111101…
…010011000010011111
32102220112010111001212
4113301331103002133
5404243224324203
615421422455035
71562522145323
oct276175230237
972815114055
1025534214303
11a913442154
124b4743447b
13253c10a860
1413432c7983
159e6a481d8
hex5f1f5309f

25534214303 has 16 divisors (see below), whose sum is σ = 27873508992. Its totient is φ = 23250240000.

The previous prime is 25534214281. The next prime is 25534214317. The reversal of 25534214303 is 30341243552.

It is not a de Polignac number, because 25534214303 - 214 = 25534197919 is a prime.

It is a super-2 number, since 2×255342143032 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 25534214303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25534214603) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 319943 + ... + 391703.

It is an arithmetic number, because the mean of its divisors is an integer number (1742094312).

Almost surely, 225534214303 is an apocalyptic number.

25534214303 is a deficient number, since it is larger than the sum of its proper divisors (2339294689).

25534214303 is a wasteful number, since it uses less digits than its factorization.

25534214303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72146.

The product of its (nonzero) digits is 43200, while the sum is 32.

Adding to 25534214303 its reverse (30341243552), we get a palindrome (55875457855).

The spelling of 25534214303 in words is "twenty-five billion, five hundred thirty-four million, two hundred fourteen thousand, three hundred three".

Divisors: 1 13 101 271 1313 3523 27371 71761 355823 932893 7247861 19447231 94222193 252814003 1964170331 25534214303