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255344702153 is a prime number
BaseRepresentation
bin1110110111001110111…
…0101111001011001001
3220102002102002212010212
43231303232233023021
513140421220432103
6313145335050505
724306452104532
oct3556356571311
9812072085125
10255344702153
1199322478072
12415a2510a35
131b10446a448
14c5045a1689
15699715e7d8
hex3b73baf2c9

255344702153 has 2 divisors, whose sum is σ = 255344702154. Its totient is φ = 255344702152.

The previous prime is 255344702111. The next prime is 255344702167. The reversal of 255344702153 is 351207443552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 253866837904 + 1477864249 = 503852^2 + 38443^2 .

It is a cyclic number.

It is not a de Polignac number, because 255344702153 - 212 = 255344698057 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 255344702153.

It is not a weakly prime, because it can be changed into another prime (255344707153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127672351076 + 127672351077.

It is an arithmetic number, because the mean of its divisors is an integer number (127672351077).

Almost surely, 2255344702153 is an apocalyptic number.

It is an amenable number.

255344702153 is a deficient number, since it is larger than the sum of its proper divisors (1).

255344702153 is an equidigital number, since it uses as much as digits as its factorization.

255344702153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504000, while the sum is 41.

The spelling of 255344702153 in words is "two hundred fifty-five billion, three hundred forty-four million, seven hundred two thousand, one hundred fifty-three".