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255355434004513 is a prime number
BaseRepresentation
bin111010000011111010010001…
…111011110111000000100001
31020111010202000020200200022211
4322003322101323313000201
5231432220412101121023
62303032400015402121
7104533551463013113
oct7203722173670041
91214122006620284
10255355434004513
11744006a4436267
1224781716223341
13ac63bb638c4cb
14470b3aa0013b3
151e7c5aa559a0d
hexe83e91ef7021

255355434004513 has 2 divisors, whose sum is σ = 255355434004514. Its totient is φ = 255355434004512.

The previous prime is 255355434004501. The next prime is 255355434004547. The reversal of 255355434004513 is 315400434553552.

255355434004513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 207061940784609 + 48293493219904 = 14389647^2 + 6949352^2 .

It is a cyclic number.

It is not a de Polignac number, because 255355434004513 - 225 = 255355400450081 is a prime.

It is not a weakly prime, because it can be changed into another prime (255355434004313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127677717002256 + 127677717002257.

It is an arithmetic number, because the mean of its divisors is an integer number (127677717002257).

Almost surely, 2255355434004513 is an apocalyptic number.

It is an amenable number.

255355434004513 is a deficient number, since it is larger than the sum of its proper divisors (1).

255355434004513 is an equidigital number, since it uses as much as digits as its factorization.

255355434004513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800000, while the sum is 49.

The spelling of 255355434004513 in words is "two hundred fifty-five trillion, three hundred fifty-five billion, four hundred thirty-four million, four thousand, five hundred thirteen".