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2553776111353 is a prime number
BaseRepresentation
bin100101001010011000111…
…010101111111011111001
3100001010202001022001210111
4211022120322233323321
5313320113141030403
65233104420544321
7352334644533235
oct45123072577371
910033661261714
102553776111353
118a5061046715
12352b325520a1
13156a87873b7c
148b863b175c5
1546669c5356d
hex25298eafef9

2553776111353 has 2 divisors, whose sum is σ = 2553776111354. Its totient is φ = 2553776111352.

The previous prime is 2553776111339. The next prime is 2553776111431. The reversal of 2553776111353 is 3531116773552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2125102119529 + 428673991824 = 1457773^2 + 654732^2 .

It is a cyclic number.

It is not a de Polignac number, because 2553776111353 - 225 = 2553742556921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2553776111297 and 2553776111306.

It is not a weakly prime, because it can be changed into another prime (2553776121353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1276888055676 + 1276888055677.

It is an arithmetic number, because the mean of its divisors is an integer number (1276888055677).

Almost surely, 22553776111353 is an apocalyptic number.

It is an amenable number.

2553776111353 is a deficient number, since it is larger than the sum of its proper divisors (1).

2553776111353 is an equidigital number, since it uses as much as digits as its factorization.

2553776111353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1984500, while the sum is 49.

The spelling of 2553776111353 in words is "two trillion, five hundred fifty-three billion, seven hundred seventy-six million, one hundred eleven thousand, three hundred fifty-three".