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2554034555143 = 10125287470843
BaseRepresentation
bin100101001010101000010…
…100101000100100000111
3100001011102001121101000201
4211022220110220210013
5313321130321231033
65233150212151331
7352344233343541
oct45125024504407
910034361541021
102554034555143
118a5183a17325
12352ba5008547
13156ac92819a6
148b88a190691
15466827a447d
hex252a8528907

2554034555143 has 4 divisors (see below), whose sum is σ = 2579322026088. Its totient is φ = 2528747084200.

The previous prime is 2554034555101. The next prime is 2554034555153. The reversal of 2554034555143 is 3415554304552.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2554034555143 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2554034555093 and 2554034555102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2554034555153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12643735321 + ... + 12643735522.

It is an arithmetic number, because the mean of its divisors is an integer number (644830506522).

Almost surely, 22554034555143 is an apocalyptic number.

2554034555143 is a deficient number, since it is larger than the sum of its proper divisors (25287470945).

2554034555143 is a wasteful number, since it uses less digits than its factorization.

2554034555143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25287470944.

The product of its (nonzero) digits is 3600000, while the sum is 46.

Adding to 2554034555143 its reverse (3415554304552), we get a palindrome (5969588859695).

The spelling of 2554034555143 in words is "two trillion, five hundred fifty-four billion, thirty-four million, five hundred fifty-five thousand, one hundred forty-three".

Divisors: 1 101 25287470843 2554034555143