Base | Representation |
---|---|
bin | 100101001010101000010… |
… | …100101000100100010001 |
3 | 100001011102001121101001002 |
4 | 211022220110220210101 |
5 | 313321130321231103 |
6 | 5233150212151345 |
7 | 352344233343554 |
oct | 45125024504421 |
9 | 10034361541032 |
10 | 2554034555153 |
11 | 8a5183a17334 |
12 | 352ba5008555 |
13 | 156ac92819b3 |
14 | 8b88a19069b |
15 | 466827a4488 |
hex | 252a8528911 |
2554034555153 has 2 divisors, whose sum is σ = 2554034555154. Its totient is φ = 2554034555152.
The previous prime is 2554034555101. The next prime is 2554034555173. The reversal of 2554034555153 is 3515554304552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2369330583169 + 184703971984 = 1539263^2 + 429772^2 .
It is a cyclic number.
It is not a de Polignac number, because 2554034555153 - 230 = 2552960813329 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2554034555098 and 2554034555107.
It is not a weakly prime, because it can be changed into another prime (2554034555173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277017277576 + 1277017277577.
It is an arithmetic number, because the mean of its divisors is an integer number (1277017277577).
Almost surely, 22554034555153 is an apocalyptic number.
It is an amenable number.
2554034555153 is a deficient number, since it is larger than the sum of its proper divisors (1).
2554034555153 is an equidigital number, since it uses as much as digits as its factorization.
2554034555153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4500000, while the sum is 47.
The spelling of 2554034555153 in words is "two trillion, five hundred fifty-four billion, thirty-four million, five hundred fifty-five thousand, one hundred fifty-three".
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