Base | Representation |
---|---|
bin | 1110110111011101101… |
… | …0000110101011011011 |
3 | 220102020201012112210021 |
4 | 3231313122012223123 |
5 | 13141033014333032 |
6 | 313155421331311 |
7 | 24311131412332 |
oct | 3556732065333 |
9 | 812221175707 |
10 | 255406402267 |
11 | 9935428a2a5 |
12 | 415bb106b37 |
13 | 1b1141911a3 |
14 | c50c862d19 |
15 | 699c79b097 |
hex | 3b77686adb |
255406402267 has 2 divisors, whose sum is σ = 255406402268. Its totient is φ = 255406402266.
The previous prime is 255406402217. The next prime is 255406402291. The reversal of 255406402267 is 762204604552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 255406402267 - 211 = 255406400219 is a prime.
It is a super-3 number, since 3×2554064022673 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (255406402217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127703201133 + 127703201134.
It is an arithmetic number, because the mean of its divisors is an integer number (127703201134).
Almost surely, 2255406402267 is an apocalyptic number.
255406402267 is a deficient number, since it is larger than the sum of its proper divisors (1).
255406402267 is an equidigital number, since it uses as much as digits as its factorization.
255406402267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 806400, while the sum is 43.
The spelling of 255406402267 in words is "two hundred fifty-five billion, four hundred six million, four hundred two thousand, two hundred sixty-seven".
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