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255411578318353 is a prime number
BaseRepresentation
bin111010000100101110100100…
…011001011010111000010001
31020111100002221001010022222221
4322010232210121122320101
5231434130403022141403
62303114243111101041
7104540610003552232
oct7204564431327021
91214302831108887
10255411578318353
1174422495438236
1224790584971781
13ac692930859a2
14470ddb4789089
151e7dc94541dbd
hexe84ba465ae11

255411578318353 has 2 divisors, whose sum is σ = 255411578318354. Its totient is φ = 255411578318352.

The previous prime is 255411578318257. The next prime is 255411578318387. The reversal of 255411578318353 is 353813875114552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 195210552537729 + 60201025780624 = 13971777^2 + 7758932^2 .

It is a cyclic number.

It is not a de Polignac number, because 255411578318353 - 241 = 253212555062801 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 255411578318291 and 255411578318300.

It is not a weakly prime, because it can be changed into another prime (255411578318053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127705789159176 + 127705789159177.

It is an arithmetic number, because the mean of its divisors is an integer number (127705789159177).

Almost surely, 2255411578318353 is an apocalyptic number.

It is an amenable number.

255411578318353 is a deficient number, since it is larger than the sum of its proper divisors (1).

255411578318353 is an equidigital number, since it uses as much as digits as its factorization.

255411578318353 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60480000, while the sum is 61.

The spelling of 255411578318353 in words is "two hundred fifty-five trillion, four hundred eleven billion, five hundred seventy-eight million, three hundred eighteen thousand, three hundred fifty-three".